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7p^2+16p-15=0
a = 7; b = 16; c = -15;
Δ = b2-4ac
Δ = 162-4·7·(-15)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-26}{2*7}=\frac{-42}{14} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+26}{2*7}=\frac{10}{14} =5/7 $
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